00:01
For this question, let do first a part b.
00:04
So, here the tr of alpha is equal to the tr of alpha beta square.
00:14
Since, beta square is equal to 1.
00:18
So, tr of alpha beta beta will be equal to minus of tr of beta alpha beta.
00:28
Since, the alpha beta is equal to 0.
00:36
So, the minus of tr of alpha beta square will be equal to minus of tr of alpha.
00:45
Since, the trace operation is cyclic.
00:49
So, the tr of alpha will be equal to 0.
00:55
So, the tr of beta will be equal to the tr of beta alpha square.
01:04
Since, alpha square is equal to 1...