Find the frequency of an electromagnetic wave with a wavelength 2.75 x 10^-8 m. A. 1.09 x 10^16 m B. 3.09 x 10^16 m C. 1.09 x 10^-16 m D. 3.09 x 10^-16 m
Added by Roger S.
Step 1
This relationship is given by the equation c = fλ, where c is the speed of light in a vacuum, approximately 3.00 x 10^8 meters per second (m/s). Show more…
Show all steps
Close
Your feedback will help us improve your experience
Prabhakar Kumar and 86 other Physics 101 Mechanics educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
What wavelength of electromagnetic radiation corresponds to a frequency of $3.46 \times 10^{13} \mathrm{~s}^{-1}$ ? a. $8.66 \times 10^{-6} \mathrm{~m}$ b. $1.15 \times 10^{5} \mathrm{~m}$ c. $7.65 \times 10^{-29} \mathrm{~m}$ d. $9.10 \times 10^{-6} \mathrm{~m}$ e. $8.99 \times 10^{-6} \mathrm{~m}$
What is the wavelength of a photon having a frequency of 52.9 x 10^14 Hz? (c = 3.00 x 10^8 m/s, h = 6.63 x 10^-34 J · s) Select one: a. 743 nm b. 1.59 x 10^24 m c. 2.48 x 10^-8 d. 5.67 x 10^-8 m
Dj T.
Calculate the frequency of visible light having a wavelength of 386 nm. A) 4.37 x 10^14 /s B) 6.17 x 10^14 /s C) 7.77 x 10^14 /s D) 2.29 x 10^15 /s E) 4.37 x 10^14 /s
Sima S.
Recommended Textbooks
University Physics with Modern Physics
Physics: Principles with Applications
Fundamentals of Physics
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD