00:01
This reaction is called halogenation of adine.
00:05
So this compound right here is adion because there are two double bonds.
00:10
Otherwise there would just be a regular alkene if there were just one double bond.
00:14
And we call it halogenation because we're reacting it with vr2, which is bromine as a halogen.
00:22
And a really important detail is that this reaction is carried out at minus 78 degrees celsius.
00:28
So what is the major product? so whether you have an alkene or a dyane, the first step of this reaction is always the same.
00:44
So we form what's called a brimonium ion intermediate.
00:48
So let's just draw this compound again.
00:52
But now we have our bromonium ion, and this is positively charged.
01:03
This is our unstable intermediates, and since we have one of the bromine atoms here, there will be a bromide ion.
01:12
Lurking around and this will serve as a nucleophile of sorts.
01:20
And this will essentially attack right here.
01:29
So this will cause the other br to act as the leaving group.
01:37
And if this bromide ion decides to attack at this carbon, then the product will look like so.
01:48
The double bond, how do we have, br here, and br here.
01:56
We have generated what is known as the 5 -6 diroma products.
02:12
So because this is a dyeing, there's actually another place where this bromide ion could attack.
02:19
So this is our first root of attack, right? it could simply attack at this carbon right here.
02:25
But interestingly enough, this ion could actually attack right here instead...