00:01
On this problem, i'm just going to look at when average speed and average velocity are the same and when are they different.
00:07
For average speed, we have v is equal to x, the distance traveled by the object divided by delta t, the time interval.
00:16
And average velocity, i just called the vx, is equal to delta x, the displacement of the object, divided by delta t, the time interval.
00:26
So just looking at these two equations, we already see that for average speed, we're dealing.
00:30
With x the distance traveled so it doesn't matter about the direction the object is changing we just care about the total distance of the object travels and for average velocity we have delta x which is displacement or the net change of the object so here we do care about the change and direction that the object undergoes first let's look at when these two are the same and we're going to say that both have the same time interval delta t so all we have to focus on is on x the distance travel and dot the x the displacement so for delta x if we say that we're only going in the positive direction starting from zero 10 meters then we'll have the final position of the object is 10 minus its initial position which is zero so we have for a displacement here 10 meters so that means for the total distance, you have the start at zero, and it just goes 10 meters.
01:34
So we have distance traveled 10 meters.
01:38
So this is when the speed and the velocity are the same.
01:46
And now let's look at when these two are different.
01:55
So again, looking at displacement, if we say we're going to start from zero, go into positive direction 20 meters, and the negative direction, 10 meters...