00:02
For the first part of the problem, the vehicle first travel 5 km along the east direction and then it travels 3 km along south direction.
00:18
So the displacement d will be given by the displacement d will be square root of 5 square plus 3 square kilometers or the displacement is 5 .83 kilometers and the distance s is 5 plus 3 kilometers, that is 8 kilometers.
00:49
Now, the average velocity equals the displacement over the time t and that is 5 .8 kilometers over the time is 30 minutes or 0 .5 .5 .000.
01:07
Hours.
01:09
So the average velocity of the vehicle is 11 .7 kilometers per hour.
01:23
And if we find out this angle theta, that is the direction of the velocity, the direction of the velocity will be tan inverse of the displacement along the south direction, that is 3 over, the displacement along east, or the angle theta, the direction will be 31 degrees south of east.
01:47
Now the average speed equals the total distance covered over the time taken.
02:01
That will be 8 km per 0 .5 hours.
02:07
So the average speed of the vehicle equals 16 kilometers per hour.
02:18
The magnitude of the average speed is greater than the magnitude of the average velocity.
02:32
Now the second part of the problem.
02:36
In this part, a car takes 35 seconds to travel 45 meter due east and 25 meter due west.
02:52
So in this situation, the first car displaced along each direction by 45 meters.
03:02
And then it traveled back to west direction and the distance covered is 25 meters.
03:09
So in that case, the displacement of the car will be given to 45...