00:01
Okay, so we're told that the probability that the printer functions is 70 % because it doesn't function, or not function, 30 % of the time.
00:13
We're then also told that the probability of making a defective bolt, if it functions, is 0 .1, and the probability of making a defective bolt, if it doesn't function, is 0 .4.
00:29
Now in part a they want us to tell them what's the probability that any given manufactured bolt turns out to be defective and using the law of conditional probability this is the probability that the bolt turns out to be defective given that the printer was functioning times the probability that it was functioning plus the probability it turns out to be defective given that it wasn't functioning times the probability that it wasn't functioning and we have all that written down up here, that's 0 .1 times 0 .7 plus 0 .4 times 0 .3.
01:02
And if we plug all that in, we get the probability of any given bolt being defective is 0 .19, to two small places.
01:15
For part b, it says what's the probability that among six manufactured bolts, exactly two of them turn out to be defective? so if we call x the number of defective bolts in 6, then x follows a binomial distribution with 6 trials and 0 .19 of success.
01:34
So the probability that x equals 2 exactly is just 6 choose 2 times 0 .19 to the 2 times 0 .81 to the 4.
01:44
And if we plug that in, we find that we get 0 .233 to three decimal places...