For \( f(x) \) to be a valid pdf, the integral of \( f(x) \) over its entire domain must equal 1. The domain of \( f(x) \) is \( 0 \leq x \leq 2 \), and \( f(x) = kx \) within this interval. Therefore, we need to solve the following integral:
\[
\int_{0}^{2} kx
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