00:01
Hello students, according to the first part, we have to prove modulus of ap is equals to modulus of av into modulus of ai.
00:17
Modulus of ap is nothing but is equals to output power divided by input power.
00:24
We can write the power value as output voltage into input current, output current divided by input voltage, input current.
00:34
So that we can take it as v naught divided by vi into i naught divided by ii.
00:45
Hereby we can write down the modulus of ap into modulus of av into modulus of ai.
00:54
It's proved.
00:59
Part two, in this we are going to substitute output power is equals to v naught square divided by 16.
01:11
The output power value will be 20 is equals to v naught square divided by 16.
01:17
By this we will get v naught value is equals to 17 .8 volt.
01:27
Now we are going to find out av value is equals to v naught by vi is equals to 17 .8 divided by 5.
01:37
By this we will get 3578 as a value.
01:43
Next we are going to find out i naught is equals to v naught divided by load resistance is equals to 17 .8 divided by 16 will give the value 1 .12 ampere.
02:01
Ii is equals to vs divided by rs plus load resistance is equals to 5 divided by 10k plus 20k...