80. Ashok and Bimal run on a 450 m long circular track at a speed of 12 m/s and 18 m/s respectively. They start at the same time but run in opposite directions. Find the number of times they would have met when Bimal covered 3240 meters. (A) 12 (B) 10 (G) 14 (D) 16
Added by Tyler C.
Step 1
First, we need to find the time it takes for Bimal to cover 3240 meters. Since Bimal's speed is 18 m/s, we can find the time by dividing the distance by the speed: Time = Distance / Speed Time = 3240 / 18 Time = 180 seconds Show more…
Show all steps
Close
Your feedback will help us improve your experience
Kratika Bhadauria and 86 other Algebra educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
Amar, Akbar and Anthony start running in the same direction and from the same point, around a circular track with speeds $7 \mathrm{~m} / \mathrm{sec}, 11 \mathrm{~m} / \mathrm{sec}$ and $22 \mathrm{~m} / \mathrm{sec}$ respectively. If Akbar can complete 5 revolutions around the track in $40 \mathrm{sec}$, when will they meet for the first time after they start? (A) $56 \mathrm{~s}$ (B) $88 \mathrm{~s}$ (C) $118 \mathrm{~s}$ (D) $79 \mathrm{~s}$
Quantitative Aptitude
Time and Distance
Two runners start simultaneously from the same point on a circular $200-m$ track and $\mathrm{run}$ in opposite directions. One runs at a constant speed of 6.20 $\mathrm{m} / \mathrm{s}$ , and the other runs at a constant speed of 5.50 $\mathrm{m} / \mathrm{s}$ . When they first mect, (a) for how long a time will they have been running, and (b) how far will each one have run along the track?
Manne A.
Recommended Textbooks
Elementary and Intermediate Algebra
Algebra and Trigonometry
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD