Question

8.2-8 A fixed-end beam AB is subjected to a symmetric triangular load of maximum intensity $q_0$ as shown in the figure. Determine all reactions, the equation of the de- flection curve, and the maximum deflection $\delta_{max}$ of the beam. Prob. 8.2-8 8.2-8 $R_A = R_B = q_0L/4$, $M_A = M_B = 5q_0L^2/96$, $v = q_0x^2(25L^3 - 40L^2x + 16x^3)/960LEI$ for $0 \le x \le L/2$, $\delta_{max} = 7q_0L^4/3840EI$

          8.2-8 A fixed-end beam AB is subjected to a symmetric
triangular load of maximum intensity $q_0$ as shown in the
figure. Determine all reactions, the equation of the de-
flection curve, and the maximum deflection $\delta_{max}$ of the
beam.

Prob. 8.2-8
8.2-8 $R_A = R_B = q_0L/4$, $M_A = M_B = 5q_0L^2/96$,
$v = q_0x^2(25L^3 - 40L^2x + 16x^3)/960LEI$ for
$0 \le x \le L/2$, $\delta_{max} = 7q_0L^4/3840EI$

8.2-8 A fixed-end beam AB is subjected to a symmetric
triangular load of maximum intensity q0 as shown in the
figure. Determine all reactions, the equation of the de-
flection curve, and the maximum deflection δmax of the
beam.

Prob. 8.2-8
8.2-8 RA = RB = q0L/4, MA = MB = 5q0L^2/96,
v = q0x^2(25L^3 - 40L^2x + 16x^3)/960LEI for
0 ≤ x ≤ L/2, δmax = 7q0L^4/3840EI

Added by Carlos T.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Ashar Tanveer

Step 1

Determine the reactions: Since the beam is fixed at both ends, there will be a reaction at each end. Let's call the reaction at A as Ra and the reaction at B as Rb. Since the load is symmetric, the reactions will also be symmetric. Therefore, Ra = Rb = R. Show more…

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8.2-8 A fixed-end beam AB is subjected to symmetric triangular load of maximum intensity 40 as shown in the figure. Determine all reactions, the equation of the deflection curve, and the maximum deflection max of the beam. Prob _ 8.2-8 8.2-8 Ra = R; 40L/4 M = M, = 5q0L^2/96, 40x^2 (2L^3/3 + 16x^3/960EI) for 0 < x < L/2 Omax = 740L^3/3840EI