0:00
Hello everyone.
00:01
So in this question it is given that x is a position variant with parameter lambda is equals to 8.
00:16
The probability density function, probability mass function for x is given as e raised to the power minus lambda, lambda raised to the power x divided by x factorial.
00:28
Now, in part a we have to find the probability first, a first probability that x is equals to 6.
00:47
So this is equals to e raised to the power minus 8, 8 raised to the power 6 divided by 6 factorial which is equals to 0 .1 221.
01:01
Second is probability that x is greater than equals to 6.
01:09
So this is equals to summation over x from 6 to infinity, e raised to the power.
01:20
We can write this as this is equal to 1 minus probability that x is less than 6.
01:28
So 1 minus probability x from 0 to 5, e raised to the power minus 8, 8 raised to the power x divided by x factorial.
01:42
So values of x will be from 0 to 5.
01:44
Summing over, we get 1 minus 0 .1912, which is nothing but equals to 0 .8088.
01:56
Now let us come to part b of the question.
02:00
What is the expected value in standard deviation of the number of small aircraft that arrive during a 90 minute period? so for b, lambda is equal to 5 multiplied by 90 divided by 60 which is equal to 12...