00:01
In this problem, we have air entering a nozzle at steadily at 200 kilopascals and 65 degrees c at a rate of 35 meters per second.
00:18
And it exits at 95 kilopascals and 240 meters per second.
00:24
The surrounding temperatures, the surrounding temperature is 17 degrees c.
00:30
And we estimate that the heat loss to this surroundings is 3 kilojoules per kilogram.
00:40
It's air, so we have an ideal gas constant of this.
00:45
And because we know two thermodynamic properties here, we can look up the anthropian and the standard entropy from tables.
00:54
And we know that there's no energy being stored in this system.
01:01
The rate of energy coming in has to be equal to the or minus the rate of energy going out has to be zero.
01:08
So they have to be equal to each other.
01:13
Because, again, there's no, well, there is no work being done.
01:23
So anyway, that gives us that the energy coming in is this, the flow of energy coming in, and the flow of energy going out.
01:31
And then we have in the fluid.
01:34
The energy going out in the heat, which i guess this would be, if you put an out on there.
01:45
So we can basically divide through, you know, multiply through by a differential time element and just get this in, well, divide through by this mass and get this all in a specific form.
01:57
So we have q -out plus delta h plus delta k -e is zero.
02:05
We know everything in here, except for h2...