A gas mixture containing only N2 and Kr is 48.7% N2 by mass. What is the partial pressure in mmHg of krypton in the mixture if the total pressure is 765 mmHg?
Added by Gabriel V.
Close
Step 1
Since the gas mixture is 48.7% N2 by mass, we can assume that 48.7% of the total pressure is due to N2. Partial pressure of N2 = 48.7% of 765 mmHg Partial pressure of N2 = (48.7/100) * 765 mmHg Partial pressure of N2 = 372.855 mmHg Show more…
Show all steps
Your feedback will help us improve your experience
Aadit Sharma and 74 other Chemistry 101 educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
A gas mixture contains 75.2% nitrogen and 24.8% krypton by mass. What is the partial pressure of krypton in the mixture if the total pressure is 745 mmHg?
A gas mixture contains 75.2$\%$ nitrogen and 24.8$\%$ krypton by mass. What is the partial pressure of krypton in the mixture if the total pressure is 745 $\mathrm{mm} \mathrm{Hg}$ ?
What is the partial pressure of krypton in the mixture if the total pressure is 718 mmHg ?A gas mixture contains 75.2% nitrogen and 24.8% krypton by mass.
Sima S.
Recommended Textbooks
Chemistry: Structure and Properties
Chemistry The Central Science
Chemistry
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD