Question

8. Rank the alkyl bromides by Sn1 reactivity. The most reactive is 1, and the least reactive is 4. 9. Rank the alkyl halides by Sn2 reactivity. The most reactive is 1, and the least reactive is 4. 10. Circle the rate equation that best fits the reaction below. a) Rate = k [ NaI ] b) Rate = k [ PhCHDBr ]^2 [ NaI ] c) Rate = k [ PhCHDBr ] [ NaI ] d) Rate = k [ PhCHDBr ] [ NaI ]^2 e) Rate = k [ PhCHDBr ]

          8. Rank the alkyl bromides by Sn1 reactivity. The most reactive is 1, and the least reactive is 4.
9. Rank the alkyl halides by Sn2 reactivity. The most reactive is 1, and the least reactive is 4.
10. Circle the rate equation that best fits the reaction below.
a) Rate = k [ NaI ]
b) Rate = k [ PhCHDBr ]^2 [ NaI ]
c) Rate = k [ PhCHDBr ] [ NaI ]
d) Rate = k [ PhCHDBr ] [ NaI ]^2
e) Rate = k [ PhCHDBr ]

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8. Rank the alkyl bromides by Sn1 reactivity. The most reactive is 1, and the least reactive is 4.
9. Rank the alkyl halides by Sn2 reactivity. The most reactive is 1, and the least reactive is 4.
10. Circle the rate equation that best fits the reaction below.
a) Rate = k [ NaI ]
b) Rate = k [ PhCHDBr ]^2 [ NaI ]
c) Rate = k [ PhCHDBr ] [ NaI ]
d) Rate = k [ PhCHDBr ] [ NaI ]^2
e) Rate = k [ PhCHDBr ]

Added by Luz M.

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

Instant Answer

Solved by Expert Madhur L

09/14/2023

Step 1

In SN1 reactions, the stability of the carbocation intermediate is the key factor. More stable carbocations will lead to higher reactivity. The order of carbocation stability is: 3° > 2° > 1° > methyl. Since we don't have the structures of the alkyl bromides, we Show more…

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Rank the alkyl bromides by Sn1 reactivity. The most reactive is 1, and the least reactive is 4. 9. Rank the alkyl halides by Sn2 reactivity. The most reactive is 1, and the least reactive is 4. 10. Circle the rate equation that best fits the reaction below. a) Rate = k [ Nal ] b) Rate = k [ PhCHDBr ]^2 [ Nal ] c) Rate = k [ PhCHDBr ] [ Nal ] d) Rate = k [ PhCHDBr ] [ Nal ]^2 e) Rate = k [ PhCHDBr ]

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Transcript

00:01 Hi, in this question, we are having three parts.

00:02 In the first part of the question we are given with these alkyl bromides and we are asked to rank them by sn1 reactivity.

00:10 We know that in sn1 reaction there is formation of carbocation intermediate and on the basis of stability of carbocation intermediate, we can rank these alkyl bromides.

00:30 Let us form the intermediates as the br - will be released and we will be getting the carbocation intermediates here in this manner.

00:44 This is allylic carbocation this is 1 degree carbocation.

00:54 This is vinylic carbocation and this is 2 degree carbocation.

01:00 If we talk about the stability order, then we can say that allylic carbocation is more stable among the given ones.

01:10 Hence, its reactivity will be greatest.

01:14 Therefore, we can say one number we can give to this.

01:19 Now, vinylic carbocation will be least stable because we are having a positive charge on double bonded carbon atom, which is not stable.

01:30 Therefore, we can put 4 number to this vinylic halide.

01:36 Now, we have to decide between 1 degree and 2 degree.

01:39 We can say 2 degree is more stable than 1 degree.

01:44 Therefore, we can put 2 number here and 3 number here.

01:48 This will be the ranking for sn1 reactivity.

01:52 Now, in second part, we are given with these alkyl halides.

01:58 We are asked to rank them in order of sn2 reactivity.

02:03 In sn2, we can say that the reactivity order is 1 degree, then 2 degree and then 3 degree.

02:14 1 degree is most reactive, 2 degree is intermediate and 3 degree is least reactive...

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