00:01
Hi, in the first question we need to find out number of moles of sulfuric acid.
00:06
We are given the molarity and the volume.
00:08
Moles will be equal to molarity multiplied by volume in liters.
00:14
On substituting value, molarity is given 0 .500 molar multiplied by volume.
00:21
That is given 250 ml.
00:23
We will divide it with 1000 for getting converted into liters and get the value 0 .125 moles of sulfuric acid.
00:31
Now for the next part, we have to find out the volume that is used in the reaction.
00:39
Now volume will be equal to number of moles divided by molarity.
00:45
On substituting value, number of moles are given as 0 .450 divided by 0 .3 molars.
00:55
Volume comes out 1500 ml.
00:59
Now for the next question, here we have to find out number of moles of ammonia.
01:08
Again using the same formula, moles will be equal to molarity multiplied by, here we have given molality, so molality multiplied by mass of solvent in kgs.
01:31
On substituting value, 0 .147 molar multiplied by 0 .475 kgs, number of moles comes out 0 .0698 moles of ammonia.
01:50
Now we have to find out its mass also.
01:53
Mass will be equal to number of moles multiplied by molar mass.
01:57
On multiplying 0 .0698 with 17 .03 gm per mole, we get the value 1 .19 gms.
02:08
Now in the next question, we have two sub parts.
02:11
Firstly, we have to calculate number of moles.
02:15
For that, we are given the density...