= 9 m 5 m 7.5 m = FRI For the left triangular loading of height 6 kN/m and width 7.5 m, FRI (0.5) (6) (7.5) 22.5 KN and its line of action is at x₁ = (2/3)(7.5) = 5 m from O 6 kN/m FRI = 15 kN For the right triangular loading of height 6 kN/m and width 4.5 m, FR2 (0.5) (6) (4.5) 13.5 KN and its line of action is at x₂ = 7.5+ (1/3)(4.5) = 9 m from O