00:01
In this problem, you're asked to draw three mechanisms.
00:03
So our first one involves a base.
00:10
So we start with our hydroxide ion.
00:14
It pulls off this hydrogen, and the bond between oxygen and hydrogen breaks.
00:20
So you're left with a negatively charged oxygen, and it comes in attacks at the carbonyl, and pushes these electrons back up on the oxygen.
00:31
So if we label this one, two, three, four, five, we're going to have a five -membered ring with oxygen in it.
00:42
And right here, we're going to have a negatively charged oxygen.
00:46
And then we add our water.
00:50
And our oxygen takes that hydrogen, and then it's protonated.
00:56
And that's our final product.
01:00
Now our second reaction we're looking at, it involves doing this reaction in acidic condition.
01:08
So we should get the same answer, but the mechanism is going to be different.
01:13
So we have our extra proton here.
01:19
So our oxygen from our carbon yield will take one of these hydrogens.
01:26
And you're going to get a few different resonance structures here.
01:31
I'm just going to draw one of them.
01:33
So you could have the double bond here.
01:40
But i'm going to do like this.
01:43
So our oxygen then attacks at that positive charge...