9 Suppose the height of American men are (approximately) normally distributed with the average 68 inches and the standard deviation is 2.5 inches. Find the percentage of American men who are: a) Between 66 and 71 inches b) Approximately 6 feet tall?
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First, we need to standardize the values using the formula z = (x - μ) / σ, where x is the given value, μ is the mean, and σ is the standard deviation. For 66 inches: z1 = (66 - 68) / 2.5 = -0.8 For 71 inches: z2 = (71 - 68) / 2.5 = 1.2 Show more…
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