00:01
For question a, we're asked to determine the rate of change of the output voltage.
00:07
So we can use a virtual short at the input terminals.
00:14
V1 is equal to v positive, which is zero volts.
00:18
So v minus minus vin, divided by 33 .33k, plus 1 .5 times 10 to negative 9, ddt of v minus minus v out is equal to zero.
00:33
Now, v minus is 0 volts.
00:35
So we'll have negative vn over 3 .33k is equal to 1 .5 nanofarids, dv0, d.
00:44
So we have dv out d t is equal to negative 45 times 10 to 3 times vn, which is negative 3 .2.
00:53
So we get 144 times 10 to the 3.
00:57
This should be 144 times 10 to the 3.
01:02
For part b, we're asked to describe the output.
01:07
So at t is equal to 100 microseconds, we'll have 144 times 10 to the 3.
01:13
This is 144 times 10 to the 3 times 100 microseconds, and that gives us 14 .4 volts.
01:21
At 200 microseconds, we get 0 volts.
01:24
So our weight form is going to look like this square weight waveform, with the peak being at 3 .2 volts, and this side right here is going to be a negative 3 .2 volts, and this goes over time.
01:38
And here i have a peak of the different time intervals...