Question

9) What is the magnitude of the electric field from 20 cm from a point charge of q = 33 nC? a 7.4 ! 10^3 N/C b 1.48 ! 10^3 N/C c 7.4 ! 10^{12} N/C

          9) What is the magnitude of the electric field from 20 cm from a point charge of
q = 33 nC?
a 7.4 ! 10^3 N/C
b 1.48 ! 10^3 N/C
c 7.4 ! 10^{12} N/C

Added by Brooke B.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Kajal Raghubanshi

01/19/2022

Step 1

The formula is E = kQ/r^2, where E is the electric field, k is Coulomb's constant (9 x 10^9 Nm^2/C^2), Q is the charge, and r is the distance from the charge. In this case, Q = 33 nC = 33 x 10^-9 C (since 1 nC = 10^-9 C) and r = 20 cm = 0.2 m (since 1 cm = 0.01 Show more…

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