00:01
Hello students in this question.
00:02
A velocity selector is being given and we need to find out the value of magnetic field applied on this velocity selector which is taken as capital letter b.
00:10
Now in order to find a value of this b, a few data are being given which includes charge of the proton, small letter q to be equal to 2 ,000 electron volts.
00:21
The electric field applied e is taken to be 94 into 10 rise to 3 volts per meter.
00:30
Mass of the proton m to be equal to 1 .67 into 10 raise to minus 27 kilogram and energy of the proton, e .n to be equal to 1 .6 into 10 raised to minus 19 jule per electron bolt.
00:48
And here we can say that the force applied on the velocity selector, capuleter f will be equal to product of magnetic field b into charge q into velocity v.
01:00
Let this be equation number 1, where this scores f will be equal to charge q into electric field, capital, e.
01:07
Let this be equation number 2.
01:09
Now we're substituting equation number 2 in equation number 1, our equation changes as q into capillator e to be equal to magnetic field b into charge q into velocity v...