Write each complex number in trigonometric form, using degree measure for the argument. $3\sqrt{3} + 3i$
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The magnitude of a complex number z = a + bi is given by |z| = √(a^2 + b^2). For 3√3 + 3i, the magnitude is |z| = √((3√3)^2 + 3^2) = √(27 + 9) = √36 = 6. Show more…
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