Question

Find the solution of the differential equation that satisfies the given initial condition. frac{du}{dt} = frac{2t + sec^2(t)}{2u}, u(0) = -6 u = -sqrt{t^2 + an t + 64}

          Find the solution of the differential equation that satisfies the given initial condition.

frac{du}{dt} = frac{2t + sec^2(t)}{2u}, u(0) = -6

u = -sqrt{t^2 + 	an t + 64}

$Find the solution of the differential equation that satisfies the given initial condition. fracdudt = frac2t + sec^2(t)2u, u(0) = -6 u = -sqrtt^2 + an t + 64$

Added by Brianna M.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Zhumagali Shomanov

06/23/2023

Step 1

We have the differential equation: du/dt = (2t + sec^2(t))/(2u) To separate the variables, we can multiply both sides by 2u and dt: 2u du = (2t + sec^2(t)) dt Show more…

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