Question

9.22 (Exam prep) A 12 g bullet travelling at 400 m/s strikes a suspended wooden block (ballistic pendulum) of mass 2.4 kg. The length of the string is 0.95 m. The bullet passes through the block and emerges with a speed of 100 m/s. (a) What is the maximum angle of the string to the vertical? Ans: 28.5°. (b) How much work was done by the bullet on the block? Ans: 2.7 J. (c) How much work is done by the block on the bullet? Ans: -900 J. (d) If energy is conserved, why do your answers for parts b) and c) not add up to zero? Ans: some energy is dissipated as heat. L $\theta$ Figure 9.22

          9.22 (Exam prep) A 12 g bullet travelling at 400 m/s strikes
a suspended wooden block (ballistic pendulum) of mass
2.4 kg. The length of the string is 0.95 m. The bullet
passes through the block and emerges with a speed of
100 m/s.
(a) What is the maximum angle of the string to the
vertical?
Ans: 28.5°.
(b) How much work was done by the bullet on the
block?
Ans: 2.7 J.
(c) How much work is done by the block on the bullet?
Ans: -900 J.
(d) If energy is conserved, why do your answers for
parts b) and c) not add up to zero?
Ans: some energy is dissipated as heat.
L
$\theta$
Figure 9.22

Show more…

9.22 (Exam prep) A 12 g bullet travelling at 400 m/s strikes
a suspended wooden block (ballistic pendulum) of mass
2.4 kg. The length of the string is 0.95 m. The bullet
passes through the block and emerges with a speed of
100 m/s.
(a) What is the maximum angle of the string to the
vertical?
Ans: 28.5°.
(b) How much work was done by the bullet on the
block?
Ans: 2.7 J.
(c) How much work is done by the block on the bullet?
Ans: -900 J.
(d) If energy is conserved, why do your answers for
parts b) and c) not add up to zero?
Ans: some energy is dissipated as heat.
L
θ
Figure 9.22

Added by Edward C.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Khoobchandra Agrawal

03/25/2021

Step 1

The initial kinetic energy (KE) of the bullet can be calculated using the formula KE = 0.5 * m * v^2, where m is the mass of the bullet and v is its velocity. KE = 0.5 * 0.012 kg * (400 m/s)^2 KE = 96 J Show more…

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9.22 (Exam prep) A 12 g bullet travelling at 400 m/s strikes a suspended wooden block (ballistic pendulum) of mass 2.4 kg. The length of the string is 0.95 m. The bullet passes through the block and emerges with a speed of 100 m/s. (a) What is the maximum angle of the string to the vertical? 4ns: 28.5 (b) How much work was done by the bullet on the block? Ans: 2.7 J. c) How much work is done by the block on the bullet? Ans:900 J. d) If energy is conserved, why do your answers for parts b) and c) not add up to zero? Ans: some energy is dissipated as heat. L Figure 9.22

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