9.3.10 Form an equivalent circuit for the transformer and primary in the network shown in Fig. P9.3.10, and use this circuit to find the current I2. 6Ω -j2 Ω j4 Ω 1:2 I1 I2 + 12/0° v + Vi V2 2Ω 24/0° V 3 Ω Ideal FIGURE P9.3.10
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The turns ratio is 1:2, so $a = \frac{N_1}{N_2} = \frac{1}{2}$. The impedance on the secondary side is $Z_2 = 2 + j4$. The reflected impedance on the primary side is $Z_1 = \frac{Z_2}{a^2} = \frac{2 + j4}{(1/2)^2} = 4(2 + j4) = 8 + j16$. Show more…
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Adi S.
This shows a circuit that includes an ideal transformer of turns ratio ̑̑ : 1. Let vs(t) = 2000cos(21t) V, R1 = 40̑̑, R2 = 70̑̑, C1 = 3̑̑F, L1 = 50mH, and ̑̑ = 5. Compute the primary coil time-dependent voltage v1(t) (that is, the voltage of node 1) and the primary current i1(t). An ideal transformer circuit Report the peak value of V1 Report the phase of V1 rad Report the peak value of I1 mA report the phase of I1 rad
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