Seatwork 3 1. The solubility of silver chloride, AgCl, is...

Seatwork 3 1. The solubility of silver chloride, AgCl, is 1.26 × 10?? M at 25 °C. Calculate the solubility product, Ksp, of AgCl. A. 1.6 × 10?¹? B. 2.9 × 10?¹¹ C. 7.5 × 10?¹² D. 9.3 × 10?¹³ E. None of the choices 2. The solubility of barium fluoride, BaF?, is 3.15 × 10?³ M at 25 °C. Calculate the solubility product, Ksp, of BaCl?. A. 2.0 × 10?? B. 4.5 × 10?? C. 7.1 × 10?? D. 9.9 × 10?? E. None of the choices 3. Calculate the molar solubility of tin (II) hydroxide in pure water. Ksp = 5.45 × 10?²? A. 1.1 × 10?? M B. 3.2 × 10?? M C. 7.4 × 10?? M D. 9.5 × 10?? M E. None of the choices 4. The Ksp of Pb(OH)? is 2.80 × 10?¹? mol/L in water at 25.0 °C. What is the concentration of hydroxide ions in equilibrium with solid lead(II) hydroxide? (Assume that the only relevant reaction is the solubility-product equilibrium.) A. 4.1 × 10?? M B. 8.2 × 10?? M C. 3.5 × 10?? M D. 7.0 × 10?? M E. None of the choices 5. The Ksp of PbBr? is 6.60 × 10?? at 25 °C. What is the concentration of Br?(aq) in a saturated solution of PbBr?(aq)? A. 0.024 M B. 0.045 M C. 0.078 M D. 0.091 M E. None of the choices 6. Sodium phosphate is added to a solution that contains 0.0099 M aluminum nitrate and 0.021 M calcium chloride. The concentration of the first ion to precipitate (either Al³? or Ca²?) decreases as its precipitate forms. What is the concentration of this ion when the second ion begins to precipitate? Ksp of AlPO? is 9.8 × 10?²² while that of Ca?(PO?)? is 2.0 × 10?²?. A. 9.89 × 10?²? M B. 1.45 × 10?¹² M C. 6.67 × 10?¹? M D. 3.35 × 10?? M E. None of the choices 7. A dilute solution of AgNO? is added slowly and continuously to a second solution containing both Cl? and CrO?²?. If the CrO?²? concentration is 0.010 M when the first trace of Ag?CrO? precipitate appears, what is the concentration of the Cl? at that point? (Ksp of AgCl is 1.77 × 10?¹?; Ksp of Ag?CrO? is 1.12 × 10?¹²) A. 1.67 × 10?? M B. 2.55 × 10?? M C. 3.72 × 10?? M D. 4.59 × 10?? M E. None of the choices

Transcript

00:01 Alright, so we're told that we have a first question.

00:03 The solubility of silver chloride, agcl, is 1 .26 times minus 5 at 25 degrees celsius.

00:11 The question says we should calculate the solubility product, ksp, of agcl.

00:16 So first, agcl, and this is ag +, that's the dissociation equation.

00:23 Equation.

00:24 And since we're given the solubility, so we have the concentration, what that means is that we have the concentration of ag plus, right, this will be 1 .26 times 10 to the power minus 5, same as 1 .26 times 10 to the power minus 5.

00:43 And so the ksp is the concentration of hg plus article e brown times chloride i that's a 1 .26 times 10 to the power minus 5 squared and of course that would give you 1 .26 minus 5 squared that gives you 1 .59 times 10 to the power minus 10 that's it right so that is the ksp and that gives you a 1 .6 that gives you option a.

01:17 So option a for question one is a.

01:21 Let's look at question two, the same thing.

01:24 You are told that the solubility of barium fluoride is 3 .15 transverse power.

01:31 What's the ksp for barium fluoride? well, we cannot use that, right? bacl2, right, would ionize your have the 2 plus plus 2 cl minus right and since we were not given the solubility for barium chloride we're given the solubility value for barium fluoride so there's no way we can calculate that all that so yeah we we can just as you none of the choices here this one is a the first one is 8 but the other one is none of the choices right for number 2 because the that information is not complete right so we're going to move except it's if it's an error right yeah except that that's the room fluoride is an error so the ksp would have just been the concentration of b2 plus which would be the times concentration of chloride ion squared right now that's how the ksv would have been calculated let's go to the next one the molar solubility of tin two hydroxide in pure water is that um which calculate the molar solubility sorry we want the molar solubility and we're given the ksp value um we are given the ksp value so let's look at that t2 hydroxide so that's s for number 3, you have xn 2.

03:13 This goes, you have sn2 plus 2oh minus.

03:19 So if the solubility of this is x, this would be 2x, which means that the ksp would be a contribution of zinc 2 times, or i just said iron squared.

03:33 Squared.

03:34 So, we're told the ksp is given to us as 3 .5, 5 .45 times 10 to the power minus 27, 5 .45 times 10 to the power minus 27.

03:53 So, 5 .45 times 10 to the power minus 27 equals equals x times 2x whole squared.

04:05 So you see that x would be 5 .45 times 10 to the power minus 27 over 4, and then the cube root of that, right? and this would give you 5 .45, exponential minus 27, divided by 4, the cube root of that and what i have here is 1 .11 times 10 to the power minus 9 molar.

04:39 That would be the molass reliability of that which is option a.

04:46 Now we're told that the ksp of lead hydroxide is that.

04:49 What concentration of hydroxide ion in equilibrium is in equilibrium with lead hydroxide? okay, so let's look at the fourth one.

04:58 We have hydroxide k.

05:02 So, pboh bracket 2.

05:05 And you have pb2 plus and 2oh minus.

05:11 So, we want to find the concentration of hydroxide i.

05:15 And we'll give it the ksp.

05:17 Again, it's very similar.

05:18 The ksp is 6 .60 times, sorry, 2 .8 times 10 to the power minus 36, i believe, or minus 16, minus 16, okay, so again, if the concentration of this is x, this would be 2x, so the ksp, be 2 .80 times 10 to the power minus 16 equals x times 2x all squared.

05:51 So the value of x would be the cube root of 2 .8 times 10 to the power minus 16 divided by 4.

06:01 And 2 .8 times 10 to the power minus 16 divided by 4.

06:06 The cube root of that would be 2 .8.

06:10 Exponential minus 16 divided by 4 cube root of that.

06:16 I have 4 .12 times 10 to the power minus 6.

06:21 But the concentration of hydroxide ion will be twice of that.

06:27 That's what we said from the beginning.

06:30 And you can multiply that, and you have 8 .24 times 10 to the power minus 6 molar.

06:38 So that means the correct option for number four is b.

06:47 Number five, what is the concentration of bromide ion? very similar to the first one we've just done.

06:58 So we start by writing the dissociation equation, pbbr2.

07:06 Two they have pb2 plus plus 2br minus the concentration of this is x this would be 2x right so the ksp is concentration of lead two times bromide iron squared right and the ksp we were told the ksp for um lead to bromide um is 6 .60 times 10 to the power minus 6 6 .60 0 times 10 to the power minus 6 equals x times 2x all squared...

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