982 The force required to separate two glass plates of area 10–2 m2 with a film of water 0.05 mm thick between them is (surface tension of water is 70 × 10–3 N/m) (A) 28 N (B) 14 N (C) 50 N (D) 38 N
Added by John K.
Step 1
Given: Surface tension of water (σ) = 70 × 10^(-3) N/m Area of the glass plates (A) = 10^(-2) m^2 Thickness of the film of water (h) = 0.05 mm = 0.05 × 10^(-3) m The force due to surface tension is given by the formula: F = σ * 2 * A / h Substitute the given Show more…
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