Question

9. If the reaction of cyclopropane (C3H6) is first order with a rate constant of 6.7 x 10-4 sec-1, and the initial concentration of C3H6 is 0.0500M a. What is the molarity of C3H6 after 30 min? b. How many minutes does it take for the C3H6 concentration to drop to 0.0100M? c. What is the half-life of C3H6?

          9. If the reaction of cyclopropane (C3H6) is
first order with a rate constant of 6.7 x 10-4
sec-1, and the initial concentration of C3H6 is
0.0500M
a. What is the molarity of C3H6 after 30
min?
b. How many minutes does it take for
the C3H6 concentration to drop to
0.0100M?
c. What is the half-life of C3H6?

9. If the reaction of cyclopropane (C3H6) is
first order with a rate constant of 6.7 x 10-4
sec-1, and the initial concentration of C3H6 is
0.0500M
a. What is the molarity of C3H6 after 30
min?
b. How many minutes does it take for
the C3H6 concentration to drop to
0.0100M?
c. What is the half-life of C3H6?

Added by Cheyenne R.

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

Instant Answer

Solved by Expert Sandra Lundell

Step 1

Plugging in the given values, we have: ln([C3H6]t/0.0500) = -(6.7 x 10^-4)(30 x 60) Simplifying, we get: ln([C3H6]t/0.0500) = -0.01206 Now, we can solve for [C3H6]t: [C3H6]t/0.0500 = e^(-0.01206) [C3H6]t = 0.0500 * e^(-0.01206) Calculating this value, we Show more…

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9. If the reaction of cyclopropane (C3H6) is first order with a rate constant of 6.7 x 10^-4 sec^-1, and the initial concentration of C3H6 is 0.0500 M: a. What is the molarity of C3H6 after 30 min? b. How many minutes does it take for the C3H6 concentration to drop to 0.0100 M? c. What is the half-life of C3H6?