00:01
So, here the equation given is s4o6 2 - changing into 2s2o3 2-.
00:13
So, we calculate the, firstly we need to calculate the oxidation number of sulphur here.
00:25
So, here we can calculate it as taking it as x, it will be we have the oxidation number of o as –2.
00:39
So, by putting these values, it will be 4 into x plus –2 into 6 because there are 6 oxygen.
00:51
So, that would be equal to total charge that is the –2, here it is given.
00:57
So, it will be 4x -12 is equals to –2 and that will be 4x is equals to –2 plus 12 that is 4x is equals to 10, x equals to 10 by 4 that is 2 .5.
01:14
So, here we have the oxidation number of sulphur as 2 .5.
01:21
Now oxidation number if we calculate s4o6 2 - here for each element...