Question

A 0.010 M HC2H3O2 (Ka = 1.8 x 10-5) solution is titrated with 0.010 M NaOH. What indicator should be used? a. thymol blue (pKIN = 1.65) b. methyl orange (pKIN = 3.46) c. methyl red (pKIN = 5.00) d. bromthymol blue (pKIN = 7.30) e. phenolphthalein (pKIN = 8.7)

Name: a 0010 m hc2h3o2 ka 18 x 10 5 solution is titrated with 0010 m naoh what indicator should be used a thymol blue pkin 165 b methyl orange pkin 346 c methyl red pkin 500 d bromthymol blue pkin 36664
Uploaded: 2023-04-10T08:43:58-08:00
Duration: 1 min 59 s
Channel: Madhur L
Description: a 0010 m hc2h3o2 ka 18 x 10 5 solution is titrated with 0010 m naoh what indicator should be used a thymol blue pkin 165 b methyl orange pkin 346 c methyl red pkin 500 d bromthymol blue pkin 36664

          A 0.010 M HC2H3O2 (Ka = 1.8 x 10-5) solution is titrated with 0.010 M NaOH. What
indicator should be used?
a. thymol blue (pKIN = 1.65) b. methyl orange (pKIN = 3.46)
c. methyl red (pKIN = 5.00) d. bromthymol blue (pKIN = 7.30)
e. phenolphthalein (pKIN = 8.7)

Added by Daniel R.

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

Instant Answer

Solved by Expert Madhur L

04/10/2023

Step 1

Let's think step by step. Show more…

Show all steps

Thanks for your feedback!

A 0.010 M HC2H3O2 (Ka = 1.8 x 10-5) solution is titrated with 0.010 M NaOH. What indicator should be used? a. thymol blue (pKIN = 1.65) b. methyl orange (pKIN = 3.46) c. methyl red (pKIN = 5.00) d. bromthymol blue (pKIN = 7.30) e. phenolphthalein (pKIN = 8.7)