A 0.0825 M solution of a weak acid has a pH of 4.22. Determine the Ka for the acid.
Added by Paul P.
Step 1
The pH is given as 4.22. We can use the formula: \[ [H^+] = 10^{-\text{pH}} = 10^{-4.22} \] Calculating this gives: \[ [H^+] \approx 5.88 \times 10^{-5} \, \text{M} \] Show more…
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