00:01
Hi, so we are to solve for the acid ionization constant or acid dissociation constant for the given acid based on the given information here.
00:10
So to solve for this we need to write our ice table first.
00:14
If we have this acid ha, this will dissociate to hydrogen ion and deconjugate base a.
00:22
And let's write our ice table initial change and equilibrium concentrations.
00:27
Initially we have 0 .085 molar, this will be zero initially.
00:32
Then this will lose some amount, this will gain plus x and this will be equivalent to 0 .085 minus x at equilibrium.
00:41
This will be x and x.
00:42
So how do we solve for kc? so remember that kc, we're not solving for kc, ka rather, acid ionization constant is equivalent to the concentration of the product side.
00:59
So hydrogen ion, this will be at equilibrium multiplied by the conjugate base, also at equilibrium over the concentration of the acid at equilibrium also.
01:10
So we don't have the value of x here, so we need to solve for the value of x first.
01:16
How do we do that? we will use the given percent ionization.
01:20
So percent ionization ionization is equivalent to the concentration of hydrogen ion or just x at equilibrium over the initial concentration of the acid and then multiply this by 100 percent.
01:40
So let's plug in the information that we have...
