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Hi.
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Now we will discuss about how to find ka dissociation constant of weak acid.
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The concentration of the butanic acid given that 0 .1 molar and percentage ionization of the buturic acid given that 1 .23%.
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As bitinic acid is the weak acid, first we will see the dissociation of the bitinic acid.
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Buteroyic acid formula is hc4 h7o2.
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He is rise to c4 h7 o2 minus plus h plus as it is weak acid there exist an equilibrium between the dissociated and undissociated forms of the acid.
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Now we will construct the i stable to find the equilibrium concentrations of these undissociated and dissociated forms.
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By constructing the i stable, i is the initial concentrations.
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Initial concentration of the vitroic acid is 0 .1.
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It is given.
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And the initial concentration of these ions is 0.
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C is the change in concentration.
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Change in concentration is minus x as it is utilized.
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And here xx moles of ions are formed.
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E is the equilibrium concentration.
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Equilibrium concentration is the difference between these two values.
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So 0 .1 minus x x...