00:02
Okay, this says you have a monoprotic weak acid, so let's say it's h .a.
00:11
Of course, it will undergo dissociation to form a -minors and the proton.
00:23
We're going to start writing, making an ic table.
00:27
So initially, already know the initial concentration is 0 .138 more.
00:34
And there's no a -minus or proton.
00:39
So that would be a change, which means the h .a., right, this weak acid, will undergo dissociation.
00:46
So let's say there will be x more be dissociated.
00:51
So that would be x more a -minors and x more h -plus be generated.
00:57
So in the end, the concentration of h -a is 0 .13a.
01:04
Minus x and a minus will be x and proton is x so the question already says in the final solution the ph is 3 .76 which means in the final solution the proton concentration is 10 to minus 3 .76 and that's equal to about 1 .3 1 .7378 times 10 to minus 4...