00:02
Okay, so in part a, we learned that the ball is dropped from rest at a certain point above the floor, but it goes up to only 0 .700 meters, so it's losing some energy during this collision.
00:17
So this collision is an inelastic collision.
00:21
So to find the velocity of the ball just before hits the floor in part b, we can use the equation v squared is equal to u squared plus 2gs, where u is initial velocity, v is final velocity, g is gravitational acceleration, and s is a displacement.
00:38
So v squared is equal to 0 plus 2 times 9 .8 times 1, and we get v squared as 4 .42 meters per second.
00:48
For part c, we can find the velocity just after this.
00:54
So we can use the same equation, v squared is equal to u squared minus 2gs, where now v is 0.
01:02
So 0 is equal to u squared minus 2 times 9 .8 times .70 meters per second...