A 0.408 M solution of benzoic acid has a pH of 2.30. What is the Ka of benzoic acid? a. 4.21 b. 1.2 × 10-2 c. 2.5 × 10-5 d. 6.2 × 10-5 e. 5.0 × 10-3
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Given concentration of benzoic acid = 0.408 M Concentration of benzoate anion = 5.01 x 10^-3 M Concentration of benzoic acid at equilibrium = 0.408 - 5.01 x 10^-3 = 0.40299 M Show more…
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