A 0.450-kg ice puck, moving east with a speed of 3.00m/s, has a head-on collision with a 0.900-kg puck initially at rest. Assuming a perfectly elastic collision, what will be the speed direction of each object after the collision?
Added by Donald M.
Step 1
Given: - Mass of puck A (m_A) = 0.450 kg - Mass of puck B (m_B) = 0.900 kg - Initial velocity of puck A (u_A) = 3.00 m/s - Initial velocity of puck B (u_B) = 0 m/s Using the conservation of linear momentum: m_A * u_A + m_B * u_B = m_A * v_A + m_B * v_B (0.450 kg Show more…
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A 0.450 kg hockey puck, moving east with a speed of 5.80 m/s has a head on collision with a 0.900 kg puck initially at rest. Assuming a perfectly elastic collision, what will be the speed and direction of each puck after the collision?
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(II) A 0.450-kg hockey puck, moving east with a speed of 5.80 m/s, has a head-on collision with a 0.900-kg puck initially at rest. Assuming a perfectly elastic collision, what will be the speed and direction of each puck after the collision?
LINEAR MOMENTUM
Elastic Collisions in One Dimension
Hockey puck $B$ rests on a smooth ice surface and is struck by a second puck $A,$ which has the same mass. Puck $A$ is initially traveling at 15.0 $\mathrm{m} / \mathrm{s}$ and is deflected $25.0^{\circ}$ from its initial direction. Assume that the collision is perfectly elastic. Find the final speed of each puck and the direction of $B$ 's velocity after the collision.
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