00:01
Hello student, in this question, let's take the east direction as the positive direction and start solving the question.
00:08
Applying conservation of momentum to the system of parks, we can write m1 u1 plus m2 u2 is equal to m1 v1 plus m2 v2.
00:22
Here m1 and m2 are the masses of the first and second parks respectively.
00:26
U1 and u2 are the initial velocities of the first and second parks respectively.
00:30
And v1 and v2 are the final velocities of the parks respectively.
00:36
Substitute the values m1 is 0 .45 kg into 5 .64 m per second plus as the second park is at rest initially, its initial velocity u2 is equal to 0.
00:50
So this term becomes equal to 0 equals 0 .45 kg into v1 plus 0 .95 kg into v2.
00:59
So we get 2 .538 equal to 0 .45 v1 plus 0 .95 v2.
01:09
Let this be equation 1.
01:12
Now for a perfectly elastic collision, we can write v1 minus v2 is equal to minus u1 minus u2.
01:21
So it equals minus 5 .64 m per second minus u2 is 0...