A 0.5 mole of gas at temperature 300 K expands isothermally from an initial volume of 2 L to 6 L. The value of gas constant, R = 8.31 J mol-1 K-1. Calculate(a) Work done by the gas (b) Heat added to the gas (c) Final pressure of the gas
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5 mol R = gas constant = 8.31 J mol-1 K-1 T = temperature = 300 K Vf = final volume = 6 L Vi = initial volume = 2 L Substituting these values into the formula, we get: W = 0.5 mol * 8.31 J mol-1 K-1 * 300 K * ln(6 L / 2 L) W = 0.5 * 8.31 * 300 * ln(3) W = 1723.7 Show more…
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