00:01
Hi, in this question we are given with a diode.
00:03
So diode which is acting so this is a diode.
00:07
This is the current id that is the diode current id and this is the voltage output.
00:12
So output voltage jd.
00:14
So then we have id is equal to so id is given by the current across the diode is 0 .7.
00:23
So 1 minus 0 .7 divided by 0 .2 k that is equal to so we have the answer for this is 1 .5 milli ampere.
00:32
Then we have the iterative method.
00:34
So using iterative analysis we have jd is equal to 0 .7 volt for id is equal to 1 milli ampere.
00:48
Then we have so id is this value.
00:52
Then we have for second case so for b we have i is equal to is into e power v minus so v divided by n into vt where n is equal to z.
01:04
So we have i2 by i1 is equal to e power nu2 minus nu1 divided by 0 .05.
01:13
Now nu2 will be equal to nu1 plus 0 .05.
01:18
So 0 .05 sin of i2 by i1.
01:22
Then we have so i is 1 .5 milli ampere...