00:01
Hi there, so for this problem, we are told that a 10 -gauge cooper wire carries a current equals to 26 ampers.
00:15
And assuming one free electron per cooper atom, we need to calculate the drift velocity of the electrons.
00:23
So we need to calculate that drift velocity.
00:28
Now we are given also the information that the cross -ceptional area, of this wire is equal to 5 .261 millimeters to the square.
00:51
So with that said, first we know that the current is defined as, well, the current is defined as n, which is the number of atoms per meter square, that times the charge of an electron, and that times the speed, the drift speed, and that times the cross -sectional area.
01:28
So we know the charge of an electron, and we need to know the drift velocity, and the gross -sectional area, we have it.
01:38
But we don't have the number of atoms, per cubic meter.
01:44
So to do that, to obtain that, we use the following equation.
01:50
That is the density of cooper times the abogratus number divided by the molar mass.
02:01
So the density of cooper, we know that it is 8 .93 times 10.
02:10
Well, this is grams, 8 .83 grams per cubic centimeter.
02:20
And this times the abogratus number, which is 6 .02 times 10 to the 23 atoms per mole.
02:35
And that divided by the molar mass, which is 63 .0 .3...