00:01
So, we have a weight of 100 grams which is tied between two springs.
00:10
Let me draw the springs.
00:12
So, this weight of 100 grams is tied between two springs.
00:17
Let k1 be the spring constant of first spring which is given to us as 110 n per meter and x1 be the distance that the spring 1 is compressed which is given to us as 21 cm which we can also write as 0 .21 meters.
00:35
And similarly, k2 be the spring constant of second spring which is given to us as 240 and x2 be the compression of the second spring which is not given to us, we have to figure out.
00:48
So, this is all that is given to us.
00:51
Now we will solve the question.
00:55
First we have to find the compression of spring 2.
01:01
So, for that potential energy of first spring and second spring will be equal.
01:11
We know that the potential energy of first spring and the potential energy of second spring will be equal to one another.
01:21
Now, the formula for potential energy of a spring, the formula for the potential energy is half kx square.
01:32
So, that means that the potential energy of first spring will become half times k1 times x1 square and the second spring it will be half times k2 times x2 square.
01:45
So, we can write, we can substitute the values and write this as 110 times half times 0 .21 whole square is equal to half times 240 times x2 whole square...