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Hi students in this question.
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A box as shown in the figure is being given, which is having a mass m.
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The horizontal folds acting on the box is taken as capillator f, the normal force is taken as capillator n.
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The weight of this box is taken as w, which is equal to product of mass into acceleration due to gravity g, and the frictional force is taken as fk, which corresponds to the kinetic friction.
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And here the acceleration of the box will be acting in this particular direction, which is taken as a.
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Now here it should be noted that the value of mass m is taken to be 100 kilogram, the coefficient of static friction is taken as mu s which is equal to 0 .65.
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On the other hand, the coefficient of kinetic friction is taken as mu k, which is equal to 0 .35.
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Now here, the acceleration of the box a is taken to be 1 .2 meter per second square.
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On the other hand, the value of acceleration due to gravity, g is taken to be 9 .8 meter per second square...