A 100 kg car is moving with a maximum velocity of 9 m/s across a circular track of radius 30 m. The maximum force of friction between the road and the car is [Pb. PMT 2000] (a) 1000 N (b) 706 N (c) 270 N (d) 200 N
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Step 1
Given: Mass of the car, m = 100 kg Velocity of the car, v = 9 m/s Radius of the circular track, r = 30 m Centripetal force, Fc = m * v^2 / r Show more…
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