A 1.00 kg mass is connected to a spring with a spring constant of 9.00 N/m. If the initial celocity is 4.00 cm/s (0.04 m/s) and the inital displacement is 0.00 cm, then what is the amplitude of the oscillations?
Added by Derrick M.
Step 1
Given: Mass (m) = 1.00 kg Initial velocity (v) = 0.04 m/s Spring constant (k) = 9.00 N/m Total energy at equilibrium position = Kinetic energy Total energy = 0.5 * m * v^2 Total energy = 0.5 * 1.00 * (0.04)^2 Total energy = 0.5 * 1.00 * 0.0016 Total energy = Show more…
Show all steps
Your feedback will help us improve your experience
Pritesh Ranjan and 91 other Physics 101 Mechanics educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
A 4.00 kg mass is connected to a spring with a spring constant of 9.00 N/m. If during the oscillation the velocity is 12.0 cm/s when the displacement is 4.00 cm, then what is the maximum velocity of the simple harmonic motion?
Madhur L.
"A spring executes SHM with mass of 10 kg attached to it. The force constant of spring is 10 N/m.If at any instant its velocity is 40 cm/sec. The displacement will be (here amplitude is0.5m) "
Dinesh C.
A spring with spring constant $k$ is suspended vertically from a support and a mass $m$ is attached. The mass is held at the point where the spring is not stretched. Then the mass is released and begins to oscillate. The lowest point in the oscillation is $20 \mathrm{cm}$ below the point where the mass was released. What is the oscillation frequency?
Recommended Textbooks
University Physics with Modern Physics
Physics: Principles with Applications
Fundamentals of Physics
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD
