00:01
Here we are given a storage tank and this is the storage tank.
00:11
It consists of acetylene which is represented as c2h2.
00:20
Then we have propane represented as c3h8.
00:26
Finally we have butane which is c4h10.
00:33
C represents carbon and h represents hydrogen.
00:36
And here it is given that the storage tank has temperature t is equal to 20 degrees celsius, that is 293 kelvin, and the pressure of the storage tank is given which is 100 kilo -pascal.
00:54
The volume of the tank is 100 meter cube.
01:00
Also we are given the partial pressure of acetylene.
01:08
Is equal to 15 kilo pascal and the partial pressure of propane is equal to 65 kilo pascal.
01:21
Therefore we need to find the partial pressure of butane.
01:27
The partial pressure of butane will be equal to the total pressure minus partial pressure of c2h2 plus partial pressure of c3h8.
01:45
This is equal to here the total pressure is 100 kioskle minus partial pressure of c2h2 is 15 klo -pascal plus c3h8 is 65 kiosk upon solving we will get the value of partial pressure of butane that is c4h10 is a 6 .5 kof.
02:07
Equal to 20 kiosk.
02:11
Now we need to calculate the mass of each component.
02:16
First let us calculate the number of mules of butane.
02:24
The number of moles of butane is equal to pressure into volume divided by universal gas constant into the temperature.
02:32
Here the pressure of butane is 20 kiosk that is 20 into 10 power 3 pascal into volume is 100 meter cubed divided by the temperature.
02:40
Universal gas constant is 8 .34 into, here the temperature is 293 kelvin.
02:49
Upon solving we will get the number of moles of butane to be 821 .08 moles.
02:58
Therefore, we need to calculate the mass of butane...