A 100 ml of 0.05 M concentration of ethyl acetate was mixed with 100 ml of 0.05 M of NaOH. After 10 min, the concentration of NaOH was 0.0435 M and after 30 min the remaining concentration of NaOH = 0.041 M. Calculate
Added by Abdallah A.
Step 1
First, we need to find the initial moles of ethyl acetate and NaOH. Initial moles of ethyl acetate = Initial concentration × Volume = 0.05 M × 0.1 L = 0.005 moles Initial moles of NaOH = Initial concentration × Volume = 0.05 M × 0.1 L = 0.005 moles Show more…
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