A 100 ml sample of hno2aq is titrated to the equivalence...

Transcript

00:05 Exactly 225 milliliter of 0 .150 molar hno2 are tritrated with a 0 .150 noh solution.

00:27 What is the ph at the equivalence point? so basically moles is nothing but.

00:34 Moles is nothing but this is equals to molarity multiplied.

00:39 By volume right so molarity is the moles per liter the units are moles per liter and volume for volume it is liters so it should be in liters right so now you can write moles of h02 will be equals to this will be 0 .15 moles per liter and this is basically multiplied by ml so this is 225 multiplied by 10 to the power minus 3 liters right so this gives us 0 .0375 moles all right now volume of nao at volume of nah at equivalence point will be equals to volume of of hno2 multiplied by concentration of hno2 and this is whole divided by concentration of nuh right now this will be equal to 225 multiplied by 0 .15 and this is whole divided by 0 .15 so this will giving us in m l right so this is 225 ml only right now this is volume of an aohh now total volume becomes therefore total volume will be equals to 450 ml 225 multiplied by 225 i'm sorry into 2 because we are adding 225 plus 225 so this is making it in total 50 ml now after end after end point all point 0 .375 moles of hno2 gets converted into 0 .03375 moles of nano2 which is sort of strong acid and strong base right now concentration of na no 2 equals to moles multiplied by thousand and this is whole divided by volume remember volume is in m l here while thousand it is divided for this is in liters this becomes whole term becomes in leaders remember so that is why we are taking like this now this becomes equal to 0 .03375 multiplied by thousand divided by 450 right now this becomes equals to 0 .075 molar right so now we will just talk about as per reaction as per reaction n -a -no -2 plus h2 o that gives us h -n -o -2 plus o -h -negative plus no -na -plus so remember whenever we are talking about this salt this is a salt right so we have to hydrolyize it so now as it releases oh h negative that means the k a is a constant k a of h n o2 so this is a literature value i'm taking this is equal to 7 .2 into 10 to the power minus 4 right so now kb becomes equals to so the hydrolysis is done for the salt so the calculation are a little bit different here so now k w by k a equals to 10 to the power minus 14 10 to the power minus 14 here.

06:55 Now this is whole divided by 7 .2 into 10 to the power minus 4.

07:02 Right.

07:03 Now this becomes equals to kb equals to 1 .39 multiplied by 10 to the power minus 11...

Question

A 10.0 mL sample of HNO2(aq) is titrated to the equivalence point with 18.5 mL of 0.150 mol/L NaOH(aq). What is the concentration of HNO2(aq)

Question

A 10.0 mL sample of HNO2(aq) is titrated to the equivalence point with 18.5 mL of 0.150 mol/L NaOH(aq). What is the concentration of HNO2(aq)

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