A 10.0-? resistor, a 2.00-mH inductor, and a 10.0-?F...

A 10.0-? resistor, a 2.00-mH inductor, and a 10.0-?F capacitor are connected in series to an AC voltage ?v = (28.0 V) sin(10000 t) source. a) Calculate the capacitive reactance of the circuit. b) Calculate the inductive reactance of the circuit. c) Calculate the impedance of the circuit. d) Calculate the maximum current delivered by the source. e) Calculate the maximum voltage across the resistor. f) Calculate the maximum voltage across the inductor. g) Calculate the maximum voltage across the capacitor. h) Calculate the average power dissipation in an RLC series circuit. i) Calculate the phase angle ?.

Transcript

00:01 Here we have a series rlc circuit which is connected across a delta v volt ac supply.

00:08 Here the value of r is equal to 10 -horm, the value of inductance is equal to 2 millie henry and the value of capacitance is equal to 10 micro -ferred.

00:16 And here we assume that the voltage across this resistance is equal to vr, voltage across this inductor is equal to vl and voltage across this capacitor is equal to v -c.

00:27 And here current flowing through this circuit is equal to it.

00:31 Now in the phager form, the supply voltage can be expressed as 28 angle 0 degree volt.

00:40 Here 28 is the maximum value of supply voltage.

00:44 And here supply frequency is equal to 10 ,000 radian per second.

00:50 Now first we will find the capacitive reactance.

00:54 Capacity reactance axi is given by 1 over omega.

00:58 Now after putting the value of omega and c we obtain xc is equal to 1 over 10 to the power 4 into here c is equal to 10 into 10 to negative 6 and by simplifying this we obtain axi is equal to 10 home.

01:17 Now next inductive reactance xl for this series rlc circuit is given by xl is equal to omega into l.

01:27 Now after putting the value of omega and l we will.

01:29 Obtain axel is equal to 10 to the power 4 into 2 into 10 to the power negative 3 and by simplifying this we obtain axel is equal to 20 om now next total impedance of this series rlc circuit is given by suppose total impedance of this series rlc circuit is equal to z so z is given by r plus j xl minus j x c now after putting the value of r x x x x x now after putting the value of r axel and axi, we obtain z equals to, here r equals to 10 plus z, axel is equal to 20 minus j, xxi is equal to 10.

02:10 And by simplifying this, we obtain z equals to 10 plus j 10.

02:15 And in the polar form, we obtain z equals to 10 root 2 angle 45 degree oom...

Question

Please give Ace some feedback