00:02
Hello student, to find the power delivered by the current source, you have to read out the circuit by removing the voltage source.
00:10
So, the circuit will look like, we are told that 100 ohm resistance is connected in series with the current source.
00:38
Now, the value of r1 is 5 ohm, r2 is 112 .5 ohm and r3 is 25 ohm and this 100 ohm and the current is 30 ampere.
00:57
Now, the equivalent resistance of this branch is r equivalent equals to 25 into 112 .5 plus 5 divided by 25 plus 112 .5 plus 5 ohm.
01:27
So, which is equals to 20 .68 ohm.
01:31
The power delivered by the current source p equals to current is 30 ampere.
01:44
So, 30 square into 100.
01:47
This is the due to the series resistance and plus 30 square into 20 .68 is in watt.
02:01
So, which is equals to 108 .6 kilowatt.
02:09
The power delivered by the current source 108 .6 kilowatt...